TypeScript union + generic type

I've got some generic type

export interface Generic<T>{...}

I want to use it as the type for some other generic e.g.

let generics: Array<Generic> = [];

Obviously that doesn't work as I haven't specified its own type. Is there a way for me to create a union type which encapsulates all possible types for T? (So I can then do let generics: Array<Union>)

For example, if my program happens to provide string, number, ClassA and InterfaceB as possibilities for T, this union type would be string | number | ClassA | InterfaceB. But I can't know/declare those upfront (which would defeat the purpose of the generic anyway)

I've tried various approaches but the "compiler" is never happy.